Base | Representation |
---|---|
bin | 11001011111011011110010… |
… | …001110011001010110100011 |
3 | 112200221201212021101122102111 |
4 | 121133123302032121112203 |
5 | 104143312420324022243 |
6 | 1034235115330500151 |
7 | 32420526350344105 |
oct | 3137336216312643 |
9 | 480851767348374 |
10 | 112111300220323 |
11 | 327a4154269938 |
12 | 106a7b07734657 |
13 | 4a73086516a61 |
14 | 1d98304551575 |
15 | ce6413a1d39d |
hex | 65f6f23995a3 |
112111300220323 has 2 divisors, whose sum is σ = 112111300220324. Its totient is φ = 112111300220322.
The previous prime is 112111300220287. The next prime is 112111300220329. The reversal of 112111300220323 is 323022003111211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112111300220323 - 29 = 112111300219811 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112111300220294 and 112111300220303.
It is not a weakly prime, because it can be changed into another prime (112111300220329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055650110161 + 56055650110162.
It is an arithmetic number, because the mean of its divisors is an integer number (56055650110162).
Almost surely, 2112111300220323 is an apocalyptic number.
112111300220323 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111300220323 is an equidigital number, since it uses as much as digits as its factorization.
112111300220323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 112111300220323 its reverse (323022003111211), we get a palindrome (435133303331534).
The spelling of 112111300220323 in words is "one hundred twelve trillion, one hundred eleven billion, three hundred million, two hundred twenty thousand, three hundred twenty-three".
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