Base | Representation |
---|---|
bin | 11001011111011011110100… |
… | …001011111100101101000011 |
3 | 112200221201221120022210022002 |
4 | 121133123310023330231003 |
5 | 104143313002240224443 |
6 | 1034235122504134215 |
7 | 32420530230163562 |
oct | 3137336413745503 |
9 | 480851846283262 |
10 | 112111333133123 |
11 | 327a41708a97a5 |
12 | 106a7b1676736b |
13 | 4a7309029b79c |
14 | 1d98308a7bbd9 |
15 | ce64168702b8 |
hex | 65f6f42fcb43 |
112111333133123 has 2 divisors, whose sum is σ = 112111333133124. Its totient is φ = 112111333133122.
The previous prime is 112111333133101. The next prime is 112111333133171. The reversal of 112111333133123 is 321331333111211.
It is a weak prime.
It is an emirp because it is prime and its reverse (321331333111211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112111333133123 - 232 = 112107038165827 is a prime.
It is not a weakly prime, because it can be changed into another prime (112111333133923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055666566561 + 56055666566562.
It is an arithmetic number, because the mean of its divisors is an integer number (56055666566562).
Almost surely, 2112111333133123 is an apocalyptic number.
112111333133123 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111333133123 is an equidigital number, since it uses as much as digits as its factorization.
112111333133123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2916, while the sum is 29.
Adding to 112111333133123 its reverse (321331333111211), we get a palindrome (433442666244334).
The spelling of 112111333133123 in words is "one hundred twelve trillion, one hundred eleven billion, three hundred thirty-three million, one hundred thirty-three thousand, one hundred twenty-three".
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