11211200011993 has 2 divisors, whose sum is σ = 11211200011994. Its totient is φ = 11211200011992.

The previous prime is 11211200011951. The next prime is 11211200012039. The reversal of 11211200011993 is 39911000211211.

11211200011993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8232980046489 + 2978219965504 = 2869317^2 + 1725752^2 .

It is an emirp because it is prime and its reverse (39911000211211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11211200011993 is a prime.

It is not a weakly prime, because it can be changed into another prime (11211200011943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605600005996 + 5605600005997.

It is an arithmetic number, because the mean of its divisors is an integer number (5605600005997).

Almost surely, 2^{11211200011993} is an apocalyptic number.

It is an amenable number.

11211200011993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211200011993 is an equidigital number, since it uses as much as digits as its factorization.

11211200011993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 31.

The spelling of 11211200011993 in words is "eleven trillion, two hundred eleven billion, two hundred million, eleven thousand, nine hundred ninety-three".