11211212411131 has 2 divisors, whose sum is σ = 11211212411132. Its totient is φ = 11211212411130.

The previous prime is 11211212411081. The next prime is 11211212411227. The reversal of 11211212411131 is 13111421211211.

It is a m-pointer prime, because the next prime (11211212411227) can be obtained adding 11211212411131 to its product of digits (96).

It is a weak prime.

It is an emirp because it is prime and its reverse (13111421211211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11211212411131 - 2¹¹ = 11211212409083 is a prime.

It is a super-3 number, since 3×11211212411131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11211212111131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605606205565 + 5605606205566.

It is an arithmetic number, because the mean of its divisors is an integer number (5605606205566).

Almost surely, 2^{11211212411131} is an apocalyptic number.

11211212411131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211212411131 is an equidigital number, since it uses as much as digits as its factorization.

11211212411131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 22.

Adding to 11211212411131 its reverse (13111421211211), we get a palindrome (24322633622342).

The spelling of 11211212411131 in words is "eleven trillion, two hundred eleven billion, two hundred twelve million, four hundred eleven thousand, one hundred thirty-one".