Base | Representation |
---|---|
bin | 10100111000011110… |
… | …11000101000010011 |
3 | 1001221022212122110101 |
4 | 22130033120220103 |
5 | 140430032311311 |
6 | 5052251113231 |
7 | 544552512103 |
oct | 123417305023 |
9 | 31838778411 |
10 | 11211213331 |
11 | 483348a56a |
12 | 220a742817 |
13 | 1098909856 |
14 | 784d71203 |
15 | 4593b0ec1 |
hex | 29c3d8a13 |
11211213331 has 4 divisors (see below), whose sum is σ = 11422745712. Its totient is φ = 10999680952.
The previous prime is 11211213317. The next prime is 11211213341. The reversal of 11211213331 is 13331211211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11211213331 - 213 = 11211205139 is a prime.
It is a super-2 number, since 2×112112133312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11211213299 and 11211213308.
It is not an unprimeable number, because it can be changed into a prime (11211213341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105766111 + ... + 105766216.
It is an arithmetic number, because the mean of its divisors is an integer number (2855686428).
Almost surely, 211211213331 is an apocalyptic number.
11211213331 is a deficient number, since it is larger than the sum of its proper divisors (211532381).
11211213331 is an equidigital number, since it uses as much as digits as its factorization.
11211213331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211532380.
The product of its digits is 108, while the sum is 19.
Adding to 11211213331 its reverse (13331211211), we get a palindrome (24542424542).
The spelling of 11211213331 in words is "eleven billion, two hundred eleven million, two hundred thirteen thousand, three hundred thirty-one".
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