Base | Representation |
---|---|
bin | 1010001100100101011001… |
… | …0101111011000011010001 |
3 | 1110200210100200202222212120 |
4 | 2203021112111323003101 |
5 | 2432141232141330113 |
6 | 35502223423244453 |
7 | 2234663536044300 |
oct | 243112625730321 |
9 | 43623320688776 |
10 | 11211313230033 |
11 | 36327670492a4 |
12 | 13109b2149729 |
13 | 6342b751b487 |
14 | 2aa8b7d82437 |
15 | 146972e41a23 |
hex | a325657b0d1 |
11211313230033 has 48 divisors (see below), whose sum is σ = 17404482041856. Its totient is φ = 6400754680320.
The previous prime is 11211313230001. The next prime is 11211313230053. The reversal of 11211313230033 is 33003231311211.
It is not a de Polignac number, because 11211313230033 - 25 = 11211313230001 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11211313229985 and 11211313230012.
It is not an unprimeable number, because it can be changed into a prime (11211313230053) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 941883760 + ... + 941895662.
It is an arithmetic number, because the mean of its divisors is an integer number (362593375872).
Almost surely, 211211313230033 is an apocalyptic number.
It is an amenable number.
11211313230033 is a deficient number, since it is larger than the sum of its proper divisors (6193168811823).
11211313230033 is a wasteful number, since it uses less digits than its factorization.
11211313230033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17094 (or 17087 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 11211313230033 its reverse (33003231311211), we get a palindrome (44214544541244).
The spelling of 11211313230033 in words is "eleven trillion, two hundred eleven billion, three hundred thirteen million, two hundred thirty thousand, thirty-three".
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