11903 has 2 divisors, whose sum is σ = 11904. Its totient is φ = 11902.

The previous prime is 11897. The next prime is 11909. The reversal of 11903 is 30911.

It can be divided in two parts, 1190 and 3, that multiplied together give a triangular number (3570 = T_{84}).

It is a balanced prime because it is at equal distance from previous prime (11897) and next prime (11909).

It is an emirp because it is prime and its reverse (30911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11903 - 2^{4} = 11887 is a prime.

It is a Chen prime.

It is a plaindrome in base 13.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5951 + 5952.

It is an arithmetic number, because the mean of its divisors is an integer number (5952).

11903 is a deficient number, since it is larger than the sum of its proper divisors (1).

11903 is an equidigital number, since it uses as much as digits as its factorization.

11903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 14.

The square root of 11903 is about 109.1008707573. The cubic root of 11903 is about 22.8324305088.

The spelling of 11903 in words is "eleven thousand, nine hundred three".

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