Base | Representation |
---|---|
bin | 11001011111011101011111… |
… | …011111000011001000100011 |
3 | 112200221220121000122212011211 |
4 | 121133131133133003020203 |
5 | 104143330144111133212 |
6 | 1034240021252050551 |
7 | 32420622646314334 |
oct | 3137353737031043 |
9 | 480856530585154 |
10 | 112113133302307 |
11 | 327a4a04a69525 |
12 | 106a8339603a57 |
13 | 4a732b921a857 |
14 | 1d98439b9a28b |
15 | ce64be90d9a7 |
hex | 65f75f7c3223 |
112113133302307 has 2 divisors, whose sum is σ = 112113133302308. Its totient is φ = 112113133302306.
The previous prime is 112113133302281. The next prime is 112113133302367. The reversal of 112113133302307 is 703203331311211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112113133302307 - 219 = 112113132778019 is a prime.
It is not a weakly prime, because it can be changed into another prime (112113133302367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056566651153 + 56056566651154.
It is an arithmetic number, because the mean of its divisors is an integer number (56056566651154).
Almost surely, 2112113133302307 is an apocalyptic number.
112113133302307 is a deficient number, since it is larger than the sum of its proper divisors (1).
112113133302307 is an equidigital number, since it uses as much as digits as its factorization.
112113133302307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 112113133302307 its reverse (703203331311211), we get a palindrome (815316464613518).
The spelling of 112113133302307 in words is "one hundred twelve trillion, one hundred thirteen billion, one hundred thirty-three million, three hundred two thousand, three hundred seven".
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