Base | Representation |
---|---|
bin | 10000010100001010011… |
… | …110001100001011000001 |
3 | 10222011220201101101220001 |
4 | 100110022132030023001 |
5 | 121332120002304333 |
6 | 2215015455520001 |
7 | 144000305016412 |
oct | 20241236141301 |
9 | 3864821341801 |
10 | 1121162150593 |
11 | 3a2533894a51 |
12 | 161356b29001 |
13 | 81957184684 |
14 | 3c39bc69809 |
15 | 1e26d77cb7d |
hex | 1050a78c2c1 |
1121162150593 has 2 divisors, whose sum is σ = 1121162150594. Its totient is φ = 1121162150592.
The previous prime is 1121162150551. The next prime is 1121162150609. The reversal of 1121162150593 is 3950512611211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1091456593984 + 29705556609 = 1044728^2 + 172353^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121162150593 - 217 = 1121162019521 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121162150993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560581075296 + 560581075297.
It is an arithmetic number, because the mean of its divisors is an integer number (560581075297).
Almost surely, 21121162150593 is an apocalyptic number.
It is an amenable number.
1121162150593 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121162150593 is an equidigital number, since it uses as much as digits as its factorization.
1121162150593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 37.
The spelling of 1121162150593 in words is "one trillion, one hundred twenty-one billion, one hundred sixty-two million, one hundred fifty thousand, five hundred ninety-three".
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