Base | Representation |
---|---|
bin | 1010001100100111111101… |
… | …1001011000101111101011 |
3 | 1110200212010200211100001112 |
4 | 2203021333121120233223 |
5 | 2432144140003111242 |
6 | 35502420030140535 |
7 | 2235016601401433 |
oct | 243117731305753 |
9 | 43625120740045 |
10 | 11212002003947 |
11 | 3632a8a920338 |
12 | 1310b6495174b |
13 | 634397129bc4 |
14 | 2aa9416372c3 |
15 | 1469b3647c82 |
hex | a327f658beb |
11212002003947 has 2 divisors, whose sum is σ = 11212002003948. Its totient is φ = 11212002003946.
The previous prime is 11212002003883. The next prime is 11212002003991. The reversal of 11212002003947 is 74930020021211.
It is a strong prime.
It is an emirp because it is prime and its reverse (74930020021211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212002003947 - 26 = 11212002003883 is a prime.
It is not a weakly prime, because it can be changed into another prime (11212002003997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606001001973 + 5606001001974.
It is an arithmetic number, because the mean of its divisors is an integer number (5606001001974).
Almost surely, 211212002003947 is an apocalyptic number.
11212002003947 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212002003947 is an equidigital number, since it uses as much as digits as its factorization.
11212002003947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
The spelling of 11212002003947 in words is "eleven trillion, two hundred twelve billion, two million, three thousand, nine hundred forty-seven".
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