Base | Representation |
---|---|
bin | 1010001100100111111101… |
… | …1001011010111110001011 |
3 | 1110200212010200211210120022 |
4 | 2203021333121122332023 |
5 | 2432144140003404232 |
6 | 35502420030251055 |
7 | 2235016601440142 |
oct | 243117731327613 |
9 | 43625120753508 |
10 | 11212002013067 |
11 | 3632a8a927179 |
12 | 1310b64956a8b |
13 | 6343971310bb |
14 | 2aa94163a759 |
15 | 1469b364a812 |
hex | a327f65af8b |
11212002013067 has 2 divisors, whose sum is σ = 11212002013068. Its totient is φ = 11212002013066.
The previous prime is 11212002013063. The next prime is 11212002013073. The reversal of 11212002013067 is 76031020021211.
It is a weak prime.
It is an emirp because it is prime and its reverse (76031020021211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212002013067 - 22 = 11212002013063 is a prime.
It is not a weakly prime, because it can be changed into another prime (11212002013063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606001006533 + 5606001006534.
It is an arithmetic number, because the mean of its divisors is an integer number (5606001006534).
Almost surely, 211212002013067 is an apocalyptic number.
11212002013067 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212002013067 is an equidigital number, since it uses as much as digits as its factorization.
11212002013067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 11212002013067 its reverse (76031020021211), we get a palindrome (87243022034278).
The spelling of 11212002013067 in words is "eleven trillion, two hundred twelve billion, two million, thirteen thousand, sixty-seven".
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