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112120433214103 = 836312657805723
BaseRepresentation
bin11001011111100100010010…
…100110000000001010010111
3112200222121102202201210121101
4121133210102212000022113
5104143440121400322403
61034243225502330531
732421301566455116
oct3137442246001227
9480877382653541
10112120433214103
11327a8010637286
12106a9836289a47
134a73bb06c03a2
141d9892d4a5c7d
15ce679a71a71d
hex65f912980297

112120433214103 has 16 divisors (see below), whose sum is σ = 113694024842496. Its totient is φ = 110552277669120.

The previous prime is 112120433214077. The next prime is 112120433214131. The reversal of 112120433214103 is 301412334021211.

It is not a de Polignac number, because 112120433214103 - 217 = 112120433083031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112120433214173) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 138752200 + ... + 139557922.

It is an arithmetic number, because the mean of its divisors is an integer number (7105876552656).

Almost surely, 2112120433214103 is an apocalyptic number.

112120433214103 is a deficient number, since it is larger than the sum of its proper divisors (1573591628393).

112120433214103 is an equidigital number, since it uses as much as digits as its factorization.

112120433214103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 809094.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 112120433214103 its reverse (301412334021211), we get a palindrome (413532767235314).

The spelling of 112120433214103 in words is "one hundred twelve trillion, one hundred twenty billion, four hundred thirty-three million, two hundred fourteen thousand, one hundred three".

Divisors: 1 83 631 2657 52373 220531 805723 1676567 66875009 139155061 508411213 2140806011 42198130679 177686898913 1350848592941 112120433214103