Base | Representation |
---|---|
bin | 110100001101011101… |
… | …1101011011111100001 |
3 | 101201101220110001001222 |
4 | 1220122323223133201 |
5 | 3314110434030303 |
6 | 123301354104425 |
7 | 11046314535422 |
oct | 1503273533741 |
9 | 351356401058 |
10 | 112121001953 |
11 | 43606423294 |
12 | 1989111b115 |
13 | a75aa5c24c |
14 | 55d8b79649 |
15 | 2db340c938 |
hex | 1a1aeeb7e1 |
112121001953 has 2 divisors, whose sum is σ = 112121001954. Its totient is φ = 112121001952.
The previous prime is 112121001943. The next prime is 112121002073. The reversal of 112121001953 is 359100121211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106244706304 + 5876295649 = 325952^2 + 76657^2 .
It is a cyclic number.
It is not a de Polignac number, because 112121001953 - 220 = 112119953377 is a prime.
It is a super-3 number, since 3×1121210019533 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (112121001943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060500976 + 56060500977.
It is an arithmetic number, because the mean of its divisors is an integer number (56060500977).
Almost surely, 2112121001953 is an apocalyptic number.
It is an amenable number.
112121001953 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121001953 is an equidigital number, since it uses as much as digits as its factorization.
112121001953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 26.
The spelling of 112121001953 in words is "one hundred twelve billion, one hundred twenty-one million, one thousand, nine hundred fifty-three".
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