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11212102211131 is a prime number
BaseRepresentation
bin1010001100101000010101…
…0111101001011000111011
31110200212101200101101110201
42203022011113221120323
52432144341131224011
635502434010023031
72235022226215603
oct243120527513073
943625350341421
1011212102211131
113633031443498
121310b92417a77
136343b1b13ab3
142aa950a7dc03
151469bc33dcc1
hexa32855e963b

11212102211131 has 2 divisors, whose sum is σ = 11212102211132. Its totient is φ = 11212102211130.

The previous prime is 11212102211087. The next prime is 11212102211257. The reversal of 11212102211131 is 13111220121211.

11212102211131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11212102211131 - 27 = 11212102211003 is a prime.

It is a super-2 number, since 2×112121022111312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11212102211099 and 11212102211108.

It is not a weakly prime, because it can be changed into another prime (11212102281131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606051105565 + 5606051105566.

It is an arithmetic number, because the mean of its divisors is an integer number (5606051105566).

Almost surely, 211212102211131 is an apocalyptic number.

11212102211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212102211131 is an equidigital number, since it uses as much as digits as its factorization.

11212102211131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 11212102211131 its reverse (13111220121211), we get a palindrome (24323322332342).

The spelling of 11212102211131 in words is "eleven trillion, two hundred twelve billion, one hundred two million, two hundred eleven thousand, one hundred thirty-one".