Base | Representation |
---|---|
bin | 1010001100101000010111… |
… | …1110001011011011000011 |
3 | 1110200212102101101120021002 |
4 | 2203022011332023123003 |
5 | 2432144401222441003 |
6 | 35502435010322215 |
7 | 2235022411115321 |
oct | 243120576133303 |
9 | 43625371346232 |
10 | 11212112312003 |
11 | 3633037112419 |
12 | 1310b9588936b |
13 | 6343b3c3c545 |
14 | 2aa95214cd11 |
15 | 1469bd186a88 |
hex | a3285f8b6c3 |
11212112312003 has 2 divisors, whose sum is σ = 11212112312004. Its totient is φ = 11212112312002.
The previous prime is 11212112311999. The next prime is 11212112312017. The reversal of 11212112312003 is 30021321121211.
11212112312003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11212112312003 - 22 = 11212112311999 is a prime.
It is a super-2 number, since 2×112121123120032 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11212112312053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606056156001 + 5606056156002.
It is an arithmetic number, because the mean of its divisors is an integer number (5606056156002).
Almost surely, 211212112312003 is an apocalyptic number.
11212112312003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212112312003 is an equidigital number, since it uses as much as digits as its factorization.
11212112312003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11212112312003 its reverse (30021321121211), we get a palindrome (41233433433214).
The spelling of 11212112312003 in words is "eleven trillion, two hundred twelve billion, one hundred twelve million, three hundred twelve thousand, three".
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