Base | Representation |
---|---|
bin | 10000010100001101111… |
… | …010111010000010111011 |
3 | 10222012001202020222022101 |
4 | 100110031322322002323 |
5 | 121332224310311141 |
6 | 2215025324004231 |
7 | 144001606560262 |
oct | 20241572720273 |
9 | 3865052228271 |
10 | 1121220010171 |
11 | 3a2563513788 |
12 | 161372390677 |
13 | 81966162301 |
14 | 3c3a580b5d9 |
15 | 1e2738ab531 |
hex | 1050deba0bb |
1121220010171 has 2 divisors, whose sum is σ = 1121220010172. Its totient is φ = 1121220010170.
The previous prime is 1121220010121. The next prime is 1121220010193. The reversal of 1121220010171 is 1710100221211.
It is a strong prime.
It is an emirp because it is prime and its reverse (1710100221211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1121220010171 - 211 = 1121220008123 is a prime.
It is a super-2 number, since 2×11212200101712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1121220010121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560610005085 + 560610005086.
It is an arithmetic number, because the mean of its divisors is an integer number (560610005086).
Almost surely, 21121220010171 is an apocalyptic number.
1121220010171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121220010171 is an equidigital number, since it uses as much as digits as its factorization.
1121220010171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 1121220010171 its reverse (1710100221211), we get a palindrome (2831320231382).
The spelling of 1121220010171 in words is "one trillion, one hundred twenty-one billion, two hundred twenty million, ten thousand, one hundred seventy-one".
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