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1121221313241 = 3373740437747
BaseRepresentation
bin10000010100001101111…
…111111000001011011001
310222012001211201011210020
4100110031333320023121
5121332230124010431
62215025411541053
7144001623625311
oct20241577701331
93865054634706
101121221313241
113a25642237a7
121613728ba789
13819664ca463
143c3a5a6a441
151e273a67696
hex1050dff82d9

1121221313241 has 4 divisors (see below), whose sum is σ = 1494961750992. Its totient is φ = 747480875492.

The previous prime is 1121221313209. The next prime is 1121221313263. The reversal of 1121221313241 is 1423131221211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1121221313241 - 25 = 1121221313209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1121221313441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186870218871 + ... + 186870218876.

It is an arithmetic number, because the mean of its divisors is an integer number (373740437748).

Almost surely, 21121221313241 is an apocalyptic number.

It is an amenable number.

1121221313241 is a deficient number, since it is larger than the sum of its proper divisors (373740437751).

1121221313241 is an equidigital number, since it uses as much as digits as its factorization.

1121221313241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 373740437750.

The product of its digits is 576, while the sum is 24.

Adding to 1121221313241 its reverse (1423131221211), we get a palindrome (2544352534452).

The spelling of 1121221313241 in words is "one trillion, one hundred twenty-one billion, two hundred twenty-one million, three hundred thirteen thousand, two hundred forty-one".

Divisors: 1 3 373740437747 1121221313241