Base | Representation |
---|---|
bin | 10000010100001110000… |
… | …011010011001001000001 |
3 | 10222012001220101202001201 |
4 | 100110032003103021001 |
5 | 121332230341210423 |
6 | 2215025443101201 |
7 | 144001634352145 |
oct | 20241603231101 |
9 | 3865056352051 |
10 | 1121222210113 |
11 | 3a2564786615 |
12 | 161373071801 |
13 | 81966752755 |
14 | 3c3a5c21225 |
15 | 1e273b932ad |
hex | 1050e0d3241 |
1121222210113 has 2 divisors, whose sum is σ = 1121222210114. Its totient is φ = 1121222210112.
The previous prime is 1121222210083. The next prime is 1121222210123. The reversal of 1121222210113 is 3110122221211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1042212308544 + 79009901569 = 1020888^2 + 281087^2 .
It is an emirp because it is prime and its reverse (3110122221211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1121222210113 - 25 = 1121222210081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121222210123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560611105056 + 560611105057.
It is an arithmetic number, because the mean of its divisors is an integer number (560611105057).
Almost surely, 21121222210113 is an apocalyptic number.
It is an amenable number.
1121222210113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121222210113 is an equidigital number, since it uses as much as digits as its factorization.
1121222210113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1121222210113 its reverse (3110122221211), we get a palindrome (4231344431324).
The spelling of 1121222210113 in words is "one trillion, one hundred twenty-one billion, two hundred twenty-two million, two hundred ten thousand, one hundred thirteen".
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