Base | Representation |
---|---|
bin | 10100111000100110… |
… | …01111001010011011 |
3 | 1001221101202221122101 |
4 | 22130103033022123 |
5 | 140430312120011 |
6 | 5052324504231 |
7 | 544564216114 |
oct | 123423171233 |
9 | 31841687571 |
10 | 11212223131 |
11 | 483400a20a |
12 | 220ab4b077 |
13 | 1098ba1375 |
14 | 78515520b |
15 | 4595102c1 |
hex | 29c4cf29b |
11212223131 has 2 divisors, whose sum is σ = 11212223132. Its totient is φ = 11212223130.
The previous prime is 11212223063. The next prime is 11212223147. The reversal of 11212223131 is 13132221211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212223131 - 219 = 11211698843 is a prime.
It is a super-2 number, since 2×112122231312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212223099 and 11212223108.
It is not a weakly prime, because it can be changed into another prime (11212221131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606111565 + 5606111566.
It is an arithmetic number, because the mean of its divisors is an integer number (5606111566).
Almost surely, 211212223131 is an apocalyptic number.
11212223131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212223131 is an equidigital number, since it uses as much as digits as its factorization.
11212223131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144, while the sum is 19.
Adding to 11212223131 its reverse (13132221211), we get a palindrome (24344444342).
The spelling of 11212223131 in words is "eleven billion, two hundred twelve million, two hundred twenty-three thousand, one hundred thirty-one".
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