Base | Representation |
---|---|
bin | 11001011111100111111111… |
… | …001010100011110000001011 |
3 | 112200222222200101010012012101 |
4 | 121133213333022203300023 |
5 | 104144021233432020133 |
6 | 1034245123404054231 |
7 | 32421502132453033 |
oct | 3137477712436013 |
9 | 480888611105171 |
10 | 112124402220043 |
11 | 327a9767a81184 |
12 | 106aa563534377 |
13 | 4a74393a7c505 |
14 | 1d98bc866c8c3 |
15 | ce692ddbc37d |
hex | 65f9ff2a3c0b |
112124402220043 has 2 divisors, whose sum is σ = 112124402220044. Its totient is φ = 112124402220042.
The previous prime is 112124402220037. The next prime is 112124402220053. The reversal of 112124402220043 is 340022204421211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112124402220043 - 237 = 111986963266571 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112124402219993 and 112124402220020.
It is not a weakly prime, because it can be changed into another prime (112124402220053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56062201110021 + 56062201110022.
It is an arithmetic number, because the mean of its divisors is an integer number (56062201110022).
Almost surely, 2112124402220043 is an apocalyptic number.
112124402220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
112124402220043 is an equidigital number, since it uses as much as digits as its factorization.
112124402220043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 112124402220043 its reverse (340022204421211), we get a palindrome (452146606641254).
The spelling of 112124402220043 in words is "one hundred twelve trillion, one hundred twenty-four billion, four hundred two million, two hundred twenty thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •