Base | Representation |
---|---|
bin | 10100111000101000… |
… | …11100110101100001 |
3 | 1001221102101010001201 |
4 | 22130110130311201 |
5 | 140430402310111 |
6 | 5052335401201 |
7 | 544600012504 |
oct | 123424346541 |
9 | 31842333051 |
10 | 11212541281 |
11 | 4834207247 |
12 | 220b083201 |
13 | 1098c83116 |
14 | 7851d913b |
15 | 4595746c1 |
hex | 29c51cd61 |
11212541281 has 2 divisors, whose sum is σ = 11212541282. Its totient is φ = 11212541280.
The previous prime is 11212541227. The next prime is 11212541293. The reversal of 11212541281 is 18214521211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9816846400 + 1395694881 = 99080^2 + 37359^2 .
It is an emirp because it is prime and its reverse (18214521211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212541281 - 213 = 11212533089 is a prime.
It is a super-2 number, since 2×112125412812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11212541881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606270640 + 5606270641.
It is an arithmetic number, because the mean of its divisors is an integer number (5606270641).
Almost surely, 211212541281 is an apocalyptic number.
It is an amenable number.
11212541281 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212541281 is an equidigital number, since it uses as much as digits as its factorization.
11212541281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1280, while the sum is 28.
The spelling of 11212541281 in words is "eleven billion, two hundred twelve million, five hundred forty-one thousand, two hundred eighty-one".
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