Base | Representation |
---|---|
bin | 11001011111101101001110… |
… | …001101010100101101001011 |
3 | 112201000112012010012021000220 |
4 | 121133231032031110231023 |
5 | 104144114241431442303 |
6 | 1034251453243401123 |
7 | 32422061336114601 |
oct | 3137551615245513 |
9 | 481015163167026 |
10 | 112130023312203 |
11 | 32801091a32996 |
12 | 106ab671b231a3 |
13 | 4a74a7b4b0250 |
14 | 1d9919d007871 |
15 | ce6b5c60b053 |
hex | 65fb4e354b4b |
112130023312203 has 32 divisors (see below), whose sum is σ = 166560665107200. Its totient is φ = 66623082615936.
The previous prime is 112130023312201. The next prime is 112130023312249. The reversal of 112130023312203 is 302213320031211.
It is not a de Polignac number, because 112130023312203 - 21 = 112130023312201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (112130023312201) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149536668 + ... + 150284646.
It is an arithmetic number, because the mean of its divisors is an integer number (5205020784600).
Almost surely, 2112130023312203 is an apocalyptic number.
112130023312203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
112130023312203 is a deficient number, since it is larger than the sum of its proper divisors (54430641794997).
112130023312203 is a wasteful number, since it uses less digits than its factorization.
112130023312203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 880571.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 112130023312203 its reverse (302213320031211), we get a palindrome (414343343343414).
The spelling of 112130023312203 in words is "one hundred twelve trillion, one hundred thirty billion, twenty-three million, three hundred twelve thousand, two hundred three".
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