Base | Representation |
---|---|
bin | 11001011111101101010011… |
… | …100000110010111110000001 |
3 | 112201000112102022122110102111 |
4 | 121133231103200302332001 |
5 | 104144114432222143402 |
6 | 1034251510143015321 |
7 | 32422063466405116 |
oct | 3137552340627601 |
9 | 481015368573374 |
10 | 112130112302977 |
11 | 32801128194a8a |
12 | 106ab69789a541 |
13 | 4a74a93a6aa02 |
14 | 1d991aab7090d |
15 | ce6b653389d7 |
hex | 65fb53832f81 |
112130112302977 has 2 divisors, whose sum is σ = 112130112302978. Its totient is φ = 112130112302976.
The previous prime is 112130112302953. The next prime is 112130112302981. The reversal of 112130112302977 is 779203211031211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107216105139441 + 4914007163536 = 10354521^2 + 2216756^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112130112302977 is a prime.
It is not a weakly prime, because it can be changed into another prime (112130112302077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065056151488 + 56065056151489.
It is an arithmetic number, because the mean of its divisors is an integer number (56065056151489).
Almost surely, 2112130112302977 is an apocalyptic number.
It is an amenable number.
112130112302977 is a deficient number, since it is larger than the sum of its proper divisors (1).
112130112302977 is an equidigital number, since it uses as much as digits as its factorization.
112130112302977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31752, while the sum is 40.
The spelling of 112130112302977 in words is "one hundred twelve trillion, one hundred thirty billion, one hundred twelve million, three hundred two thousand, nine hundred seventy-seven".
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