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1121302001473 is a prime number
BaseRepresentation
bin10000010100010010110…
…011101011011101000001
310222012021110112120020021
4100110102303223131001
5121332411303021343
62215041413213441
7144003623516053
oct20242263533501
93865243476207
101121302001473
113a25a5824a95
12161395931281
138197a13bb84
143c3b26718d3
151e27aba50ed
hex10512ceb741

1121302001473 has 2 divisors, whose sum is σ = 1121302001474. Its totient is φ = 1121302001472.

The previous prime is 1121302001213. The next prime is 1121302001489. The reversal of 1121302001473 is 3741002031211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1076422850064 + 44879151409 = 1037508^2 + 211847^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121302001473 - 221 = 1121299904321 is a prime.

It is not a weakly prime, because it can be changed into another prime (1121303001473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560651000736 + 560651000737.

It is an arithmetic number, because the mean of its divisors is an integer number (560651000737).

Almost surely, 21121302001473 is an apocalyptic number.

It is an amenable number.

1121302001473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121302001473 is an equidigital number, since it uses as much as digits as its factorization.

1121302001473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 1121302001473 its reverse (3741002031211), we get a palindrome (4862304032684).

The spelling of 1121302001473 in words is "one trillion, one hundred twenty-one billion, three hundred two million, one thousand, four hundred seventy-three".