11213041121433 has 12 divisors (see below), whose sum is σ = 16462133231908. Its totient is φ = 7352813849760.

The previous prime is 11213041121431. The next prime is 11213041121453. The reversal of 11213041121433 is 33412114031211.

11213041121433 is a `hidden beast` number, since 1 + 1 + 2 + 1 + 3 + 0 + 411 + 214 + 33 = 666.

11213041121433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 6371646220944 + 4841394900489 = 2524212^2 + 2200317^2 .

It is not a de Polignac number, because 11213041121433 - 2¹ = 11213041121431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11213041121397 and 11213041121406.

It is not an unprimeable number, because it can be changed into a prime (11213041121431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10212240910 + ... + 10212242007.

Almost surely, 2^{11213041121433} is an apocalyptic number.

It is an amenable number.

11213041121433 is a deficient number, since it is larger than the sum of its proper divisors (5249092110475).

11213041121433 is a wasteful number, since it uses less digits than its factorization.

11213041121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20424482984 (or 20424482981 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 11213041121433 its reverse (33412114031211), we get a palindrome (44625155152644).

The spelling of 11213041121433 in words is "eleven trillion, two hundred thirteen billion, forty-one million, one hundred twenty-one thousand, four hundred thirty-three".