112131020257 has 2 divisors, whose sum is σ = 112131020258. Its totient is φ = 112131020256.

The previous prime is 112131020191. The next prime is 112131020279. The reversal of 112131020257 is 752020131211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95347558656 + 16783461601 = 308784^2 + 129551^2 .

It is an emirp because it is prime and its reverse (752020131211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112131020257 is a prime.

It is a super-3 number, since 3×112131020257³ (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (112131020557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065510128 + 56065510129.

It is an arithmetic number, because the mean of its divisors is an integer number (56065510129).

Almost surely, 2^112131020257 is an apocalyptic number.

It is an amenable number.

112131020257 is a deficient number, since it is larger than the sum of its proper divisors (1).

112131020257 is an equidigital number, since it uses as much as digits as its factorization.

112131020257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 112131020257 its reverse (752020131211), we get a palindrome (864151151468).

The spelling of 112131020257 in words is "one hundred twelve billion, one hundred thirty-one million, twenty thousand, two hundred fifty-seven".