Search a number
-
+
112131121012201 is a prime number
BaseRepresentation
bin11001011111101110001111…
…101000101101110111101001
3112201000122000121201012100101
4121133232033220231313221
5104144124013434342301
61034252154215105401
732422130465321254
oct3137561750556751
9481018017635311
10112131121012201
11328015a5617175
12106ab919672261
134a74bc4a37085
141d99264b0809b
15ce6bc3b8a701
hex65fb8fa2dde9

112131121012201 has 2 divisors, whose sum is σ = 112131121012202. Its totient is φ = 112131121012200.

The previous prime is 112131121012189. The next prime is 112131121012217. The reversal of 112131121012201 is 102210121131211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95332180992400 + 16798940019801 = 9763820^2 + 4098651^2 .

It is a cyclic number.

It is not a de Polignac number, because 112131121012201 - 27 = 112131121012073 is a prime.

It is a super-2 number, since 2×1121311210122012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112131121012291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065560506100 + 56065560506101.

It is an arithmetic number, because the mean of its divisors is an integer number (56065560506101).

Almost surely, 2112131121012201 is an apocalyptic number.

It is an amenable number.

112131121012201 is a deficient number, since it is larger than the sum of its proper divisors (1).

112131121012201 is an equidigital number, since it uses as much as digits as its factorization.

112131121012201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 112131121012201 its reverse (102210121131211), we get a palindrome (214341242143412).

The spelling of 112131121012201 in words is "one hundred twelve trillion, one hundred thirty-one billion, one hundred twenty-one million, twelve thousand, two hundred one".