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11213142131 is a prime number
BaseRepresentation
bin10100111000101101…
…01111100001110011
31001221110111122021102
422130112233201303
5140431031022011
65052400315015
7544605064322
oct123426574163
931843448242
1011213142131
114834587714
12220b312a6b
131099133759
147853140b9
1545964273b
hex29c5af873

11213142131 has 2 divisors, whose sum is σ = 11213142132. Its totient is φ = 11213142130.

The previous prime is 11213142113. The next prime is 11213142139. The reversal of 11213142131 is 13124131211.

Together with previous prime (11213142113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13124131211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11213142131 - 226 = 11146033267 is a prime.

It is a super-2 number, since 2×112131421312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11213142139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606571065 + 5606571066.

It is an arithmetic number, because the mean of its divisors is an integer number (5606571066).

Almost surely, 211213142131 is an apocalyptic number.

11213142131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213142131 is an equidigital number, since it uses as much as digits as its factorization.

11213142131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 20.

Adding to 11213142131 its reverse (13124131211), we get a palindrome (24337273342).

The spelling of 11213142131 in words is "eleven billion, two hundred thirteen million, one hundred forty-two thousand, one hundred thirty-one".