112131440433 has 12 divisors (see below), whose sum is σ = 162224328448. Its totient is φ = 74635820280.

The previous prime is 112131440423. The next prime is 112131440441. The reversal of 112131440433 is 334044131211.

112131440433 is a `hidden beast` number, since 1 + 1 + 213 + 1 + 440 + 4 + 3 + 3 = 666.

It is not a de Polignac number, because 112131440433 - 2¹⁶ = 112131374897 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 112131440397 and 112131440406.

It is not an unprimeable number, because it can be changed into a prime (112131440423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9866785 + ... + 9878142.

Almost surely, 2^112131440433 is an apocalyptic number.

It is an amenable number.

112131440433 is a deficient number, since it is larger than the sum of its proper divisors (50092888015).

112131440433 is a wasteful number, since it uses less digits than its factorization.

112131440433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19745564 (or 19745561 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 112131440433 its reverse (334044131211), we get a palindrome (446175571644).

The spelling of 112131440433 in words is "one hundred twelve billion, one hundred thirty-one million, four hundred forty thousand, four hundred thirty-three".