112133300020033 has 4 divisors (see below), whose sum is σ = 112134342442708. Its totient is φ = 112132257597360.

The previous prime is 112133300019947. The next prime is 112133300020067. The reversal of 112133300020033 is 330020003331211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 28941516391824 + 83191783628209 = 5379732^2 + 9120953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112133300020033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112133300019986 and 112133300020013.

It is not an unprimeable number, because it can be changed into a prime (112133300020633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 521049966 + ... + 521265127.

It is an arithmetic number, because the mean of its divisors is an integer number (28033585610677).

Almost surely, 2^{112133300020033} is an apocalyptic number.

It is an amenable number.

112133300020033 is a deficient number, since it is larger than the sum of its proper divisors (1042422675).

112133300020033 is a wasteful number, since it uses less digits than its factorization.

112133300020033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1042422674.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 112133300020033 its reverse (330020003331211), we get a palindrome (442153303351244).

The spelling of 112133300020033 in words is "one hundred twelve trillion, one hundred thirty-three billion, three hundred million, twenty thousand, thirty-three".