Base | Representation |
---|---|
bin | 10000010100010100101… |
… | …011001100010000110001 |
3 | 10222012100122111021020212 |
4 | 100110110223030100301 |
5 | 121332442313042433 |
6 | 2215044452513505 |
7 | 144004454022551 |
oct | 20242453142061 |
9 | 3865318437225 |
10 | 1121333330993 |
11 | 3a2611483357 |
12 | 1613a431b895 |
13 | 8198378b055 |
14 | 3c3b68a9161 |
15 | 1e27d7e2d48 |
hex | 10514acc431 |
1121333330993 has 2 divisors, whose sum is σ = 1121333330994. Its totient is φ = 1121333330992.
The previous prime is 1121333330891. The next prime is 1121333331037. The reversal of 1121333330993 is 3990333331211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1119095284129 + 2238046864 = 1057873^2 + 47308^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121333330993 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1121333330993.
It is not a weakly prime, because it can be changed into another prime (1121333330693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560666665496 + 560666665497.
It is an arithmetic number, because the mean of its divisors is an integer number (560666665497).
Almost surely, 21121333330993 is an apocalyptic number.
It is an amenable number.
1121333330993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121333330993 is an equidigital number, since it uses as much as digits as its factorization.
1121333330993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 118098, while the sum is 41.
The spelling of 1121333330993 in words is "one trillion, one hundred twenty-one billion, three hundred thirty-three million, three hundred thirty thousand, nine hundred ninety-three".
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