Base | Representation |
---|---|
bin | 110100001101110101… |
… | …1000101101011110001 |
3 | 101201102202211110011001 |
4 | 1220123223011223301 |
5 | 3314122124230001 |
6 | 123302520322001 |
7 | 11046525266665 |
oct | 1503353055361 |
9 | 351382743131 |
10 | 112133430001 |
11 | 436124416aa |
12 | 19895313301 |
13 | a7604c1018 |
14 | 55da6928a5 |
15 | 2db4565001 |
hex | 1a1bac5af1 |
112133430001 has 2 divisors, whose sum is σ = 112133430002. Its totient is φ = 112133430000.
The previous prime is 112133429963. The next prime is 112133430037. The reversal of 112133430001 is 100034331211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96830502976 + 15302927025 = 311176^2 + 123705^2 .
It is an emirp because it is prime and its reverse (100034331211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112133430001 - 233 = 103543495409 is a prime.
It is a super-2 number, since 2×1121334300012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112133430061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066715000 + 56066715001.
It is an arithmetic number, because the mean of its divisors is an integer number (56066715001).
Almost surely, 2112133430001 is an apocalyptic number.
It is an amenable number.
112133430001 is a deficient number, since it is larger than the sum of its proper divisors (1).
112133430001 is an equidigital number, since it uses as much as digits as its factorization.
112133430001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 112133430001 its reverse (100034331211), we get a palindrome (212167761212).
The spelling of 112133430001 in words is "one hundred twelve billion, one hundred thirty-three million, four hundred thirty thousand, one".
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