Base | Representation |
---|---|
bin | 10100111000101111… |
… | …11000010000000010 |
3 | 1001221111001202212200 |
4 | 22130113320100002 |
5 | 140431120040002 |
6 | 5052410534030 |
7 | 544610444622 |
oct | 123427702002 |
9 | 31844052780 |
10 | 11213440002 |
11 | 4834770496 |
12 | 220b437316 |
13 | 10992091cb |
14 | 785390882 |
15 | 4596a0b1c |
hex | 29c5f8402 |
11213440002 has 48 divisors (see below), whose sum is σ = 25047696960. Its totient is φ = 3622906656.
The previous prime is 11213439961. The next prime is 11213440003. The reversal of 11213440002 is 20004431211.
11213440002 is a `hidden beast` number, since 11 + 213 + 440 + 0 + 0 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (11213440003) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 143149 + ... + 207167.
It is an arithmetic number, because the mean of its divisors is an integer number (521827020).
Almost surely, 211213440002 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11213440002, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12523848480).
11213440002 is an abundant number, since it is smaller than the sum of its proper divisors (13834256958).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11213440002 is a wasteful number, since it uses less digits than its factorization.
11213440002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64327 (or 64324 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
Adding to 11213440002 its reverse (20004431211), we get a palindrome (31217871213).
The spelling of 11213440002 in words is "eleven billion, two hundred thirteen million, four hundred forty thousand, two".
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