Base | Representation |
---|---|
bin | 11001011111110100000111… |
… | …111111101010011000101001 |
3 | 112201001020022200002020120220 |
4 | 121133310013333222120221 |
5 | 104144224431411313312 |
6 | 1034255120535240253 |
7 | 32422443116461305 |
oct | 3137640777523051 |
9 | 481036280066526 |
10 | 112137435260457 |
11 | 32804245873362 |
12 | 106b0ba0219089 |
13 | 4a7568cc4c049 |
14 | 1d996a3558d05 |
15 | ce6e43198c8c |
hex | 65fd07fea629 |
112137435260457 has 8 divisors (see below), whose sum is σ = 149517470845440. Its totient is φ = 74757844924560.
The previous prime is 112137435260449. The next prime is 112137435260467. The reversal of 112137435260457 is 754062534731211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 112137435260457 - 23 = 112137435260449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (112137435260437) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110724169 + ... + 111732342.
It is an arithmetic number, because the mean of its divisors is an integer number (18689683855680).
Almost surely, 2112137435260457 is an apocalyptic number.
It is an amenable number.
112137435260457 is a deficient number, since it is larger than the sum of its proper divisors (37380035584983).
112137435260457 is a wasteful number, since it uses less digits than its factorization.
112137435260457 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222624543.
The product of its (nonzero) digits is 4233600, while the sum is 51.
Adding to 112137435260457 its reverse (754062534731211), we get a palindrome (866199969991668).
The spelling of 112137435260457 in words is "one hundred twelve trillion, one hundred thirty-seven billion, four hundred thirty-five million, two hundred sixty thousand, four hundred fifty-seven".
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