Base | Representation |
---|---|
bin | 1010001100101111011100… |
… | …1010000100001001101001 |
3 | 1110201001022201120210002012 |
4 | 2203023313022010021221 |
5 | 2432212243340101403 |
6 | 35503351243245305 |
7 | 2235120436625426 |
oct | 243136712041151 |
9 | 43631281523065 |
10 | 11214011253353 |
11 | 3633921005137 |
12 | 1311425819835 |
13 | 63462749228c |
14 | 2aaa9241cd4d |
15 | 146a7ec35ed8 |
hex | a32f7284269 |
11214011253353 has 2 divisors, whose sum is σ = 11214011253354. Its totient is φ = 11214011253352.
The previous prime is 11214011253349. The next prime is 11214011253437. The reversal of 11214011253353 is 35335211041211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6889953016384 + 4324058236969 = 2624872^2 + 2079437^2 .
It is a cyclic number.
It is not a de Polignac number, because 11214011253353 - 22 = 11214011253349 is a prime.
It is not a weakly prime, because it can be changed into another prime (11214011253253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607005626676 + 5607005626677.
It is an arithmetic number, because the mean of its divisors is an integer number (5607005626677).
Almost surely, 211214011253353 is an apocalyptic number.
It is an amenable number.
11214011253353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11214011253353 is an equidigital number, since it uses as much as digits as its factorization.
11214011253353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 11214011253353 its reverse (35335211041211), we get a palindrome (46549222294564).
The spelling of 11214011253353 in words is "eleven trillion, two hundred fourteen billion, eleven million, two hundred fifty-three thousand, three hundred fifty-three".
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