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11214051455153 is a prime number
BaseRepresentation
bin1010001100101111100110…
…0011011011000010110001
31110201001102112020020120202
42203023321203123002301
52432212334133031103
635503355241044545
72235121435424021
oct243137143330261
943631375206522
1011214051455153
113633941773368
121311437186755
136346328c9921
142aaa978c5a81
15146a83527988
hexa32f98db0b1

11214051455153 has 2 divisors, whose sum is σ = 11214051455154. Its totient is φ = 11214051455152.

The previous prime is 11214051455141. The next prime is 11214051455209. The reversal of 11214051455153 is 35155415041211.

11214051455153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11136156319744 + 77895135409 = 3337088^2 + 279097^2 .

It is a cyclic number.

It is not a de Polignac number, because 11214051455153 - 238 = 10939173548209 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11214051458153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607025727576 + 5607025727577.

It is an arithmetic number, because the mean of its divisors is an integer number (5607025727577).

Almost surely, 211214051455153 is an apocalyptic number.

It is an amenable number.

11214051455153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11214051455153 is an equidigital number, since it uses as much as digits as its factorization.

11214051455153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60000, while the sum is 38.

Adding to 11214051455153 its reverse (35155415041211), we get a palindrome (46369466496364).

The spelling of 11214051455153 in words is "eleven trillion, two hundred fourteen billion, fifty-one million, four hundred fifty-five thousand, one hundred fifty-three".