Base | Representation |
---|---|
bin | 10000010100011001001… |
… | …111110100001000000001 |
3 | 10222012112222211111200002 |
4 | 100110121033310020001 |
5 | 121333121432242241 |
6 | 2215100233005345 |
7 | 144006405032114 |
oct | 20243117641001 |
9 | 3865488744602 |
10 | 1121410040321 |
11 | 3a265080719a |
12 | 161405b53855 |
13 | 8199663869c |
14 | 3c3c2b5657b |
15 | 1e2853e689b |
hex | 105193f4201 |
1121410040321 has 2 divisors, whose sum is σ = 1121410040322. Its totient is φ = 1121410040320.
The previous prime is 1121410040287. The next prime is 1121410040327. The reversal of 1121410040321 is 1230400141211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1097809399696 + 23600640625 = 1047764^2 + 153625^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121410040321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1121410040293 and 1121410040302.
It is not a weakly prime, because it can be changed into another prime (1121410040327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560705020160 + 560705020161.
It is an arithmetic number, because the mean of its divisors is an integer number (560705020161).
Almost surely, 21121410040321 is an apocalyptic number.
It is an amenable number.
1121410040321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121410040321 is an equidigital number, since it uses as much as digits as its factorization.
1121410040321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1121410040321 its reverse (1230400141211), we get a palindrome (2351810181532).
The spelling of 1121410040321 in words is "one trillion, one hundred twenty-one billion, four hundred ten million, forty thousand, three hundred twenty-one".
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