Base | Representation |
---|---|
bin | 1010001100110000001010… |
… | …0011011001011010001001 |
3 | 1110201001211001100020112002 |
4 | 2203030002203121122021 |
5 | 2432213141311142101 |
6 | 35503422233200345 |
7 | 2235125251001006 |
oct | 243140243313211 |
9 | 43631731306462 |
10 | 11214202443401 |
11 | 3633a09a20041 |
12 | 13114798600b5 |
13 | 634657c83599 |
14 | 2aaaad98a8ad |
15 | 146a918eed6b |
hex | a33028d9689 |
11214202443401 has 2 divisors, whose sum is σ = 11214202443402. Its totient is φ = 11214202443400.
The previous prime is 11214202443343. The next prime is 11214202443439. The reversal of 11214202443401 is 10434420241211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5932244784400 + 5281957659001 = 2435620^2 + 2298251^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11214202443401 is a prime.
It is not a weakly prime, because it can be changed into another prime (11214202443481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607101221700 + 5607101221701.
It is an arithmetic number, because the mean of its divisors is an integer number (5607101221701).
Almost surely, 211214202443401 is an apocalyptic number.
It is an amenable number.
11214202443401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11214202443401 is an equidigital number, since it uses as much as digits as its factorization.
11214202443401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 11214202443401 its reverse (10434420241211), we get a palindrome (21648622684612).
The spelling of 11214202443401 in words is "eleven trillion, two hundred fourteen billion, two hundred two million, four hundred forty-three thousand, four hundred one".
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