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112143241433051 is a prime number
BaseRepresentation
bin11001011111111001100010…
…000100011100111111011011
3112201001210022022102101001022
4121133321202010130333123
5104144323324301324201
61034301521025513055
732423040031231223
oct3137714204347733
9481053268371038
10112143241433051
1132806755247804
12106b21407a278b
134a760a6b1222a
141d99a94711083
15ce7182c9641b
hex65fe6211cfdb

112143241433051 has 2 divisors, whose sum is σ = 112143241433052. Its totient is φ = 112143241433050.

The previous prime is 112143241433029. The next prime is 112143241433057. The reversal of 112143241433051 is 150334142341211.

It is a strong prime.

It is an emirp because it is prime and its reverse (150334142341211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112143241433051 is a prime.

It is a super-2 number, since 2×1121432414330512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112143241433057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56071620716525 + 56071620716526.

It is an arithmetic number, because the mean of its divisors is an integer number (56071620716526).

Almost surely, 2112143241433051 is an apocalyptic number.

112143241433051 is a deficient number, since it is larger than the sum of its proper divisors (1).

112143241433051 is an equidigital number, since it uses as much as digits as its factorization.

112143241433051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 112143241433051 its reverse (150334142341211), we get a palindrome (262477383774262).

The spelling of 112143241433051 in words is "one hundred twelve trillion, one hundred forty-three billion, two hundred forty-one million, four hundred thirty-three thousand, fifty-one".