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112144412113 is a prime number
BaseRepresentation
bin110100001110001010…
…0111110110111010001
3101201110112111101202221
41220130110332313101
53314132432141423
6123303551541041
711050020526546
oct1503424766721
9351415441687
10112144412113
1143618662728
1219898b2a781
13a762867906
1455dbd10bcd
152db54d3e5d
hex1a1c53edd1

112144412113 has 2 divisors, whose sum is σ = 112144412114. Its totient is φ = 112144412112.

The previous prime is 112144412099. The next prime is 112144412131. The reversal of 112144412113 is 311214441211.

Together with next prime (112144412131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83629699344 + 28514712769 = 289188^2 + 168863^2 .

It is a cyclic number.

It is not a de Polignac number, because 112144412113 - 225 = 112110857681 is a prime.

It is a super-2 number, since 2×1121444121132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112144412143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56072206056 + 56072206057.

It is an arithmetic number, because the mean of its divisors is an integer number (56072206057).

Almost surely, 2112144412113 is an apocalyptic number.

It is an amenable number.

112144412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112144412113 is an equidigital number, since it uses as much as digits as its factorization.

112144412113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 768, while the sum is 25.

Adding to 112144412113 its reverse (311214441211), we get a palindrome (423358853324).

The spelling of 112144412113 in words is "one hundred twelve billion, one hundred forty-four million, four hundred twelve thousand, one hundred thirteen".