Base | Representation |
---|---|
bin | 10000010100101101011… |
… | …010101100100111101011 |
3 | 10222020102120120212022022 |
4 | 100110231122230213223 |
5 | 121334320044444413 |
6 | 2215154002015055 |
7 | 144020654252552 |
oct | 20245532544753 |
9 | 3866376525268 |
10 | 1121748437483 |
11 | 3a2804826a73 |
12 | 16149b34748b |
13 | 81a1b78b5ab |
14 | 3c415a82d99 |
15 | 1e2a4e8c608 |
hex | 1052d6ac9eb |
1121748437483 has 2 divisors, whose sum is σ = 1121748437484. Its totient is φ = 1121748437482.
The previous prime is 1121748437437. The next prime is 1121748437489. The reversal of 1121748437483 is 3847348471211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121748437483 - 212 = 1121748433387 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121748437489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560874218741 + 560874218742.
It is an arithmetic number, because the mean of its divisors is an integer number (560874218742).
Almost surely, 21121748437483 is an apocalyptic number.
1121748437483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121748437483 is an equidigital number, since it uses as much as digits as its factorization.
1121748437483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3612672, while the sum is 53.
The spelling of 1121748437483 in words is "one trillion, one hundred twenty-one billion, seven hundred forty-eight million, four hundred thirty-seven thousand, four hundred eighty-three".
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