Base | Representation |
---|---|
bin | 10000010100111100011… |
… | …010110000010101101001 |
3 | 10222021002010011012101221 |
4 | 100110330122300111221 |
5 | 121340324012022303 |
6 | 2215234552142041 |
7 | 144030131404501 |
oct | 20247432602551 |
9 | 3867063135357 |
10 | 1122000110953 |
11 | 3a29238a2a77 |
12 | 16154b697921 |
13 | 81a5b9688c7 |
14 | 3c43b276a01 |
15 | 1e2bc1024bd |
hex | 1053c6b0569 |
1122000110953 has 2 divisors, whose sum is σ = 1122000110954. Its totient is φ = 1122000110952.
The previous prime is 1122000110929. The next prime is 1122000111007. The reversal of 1122000110953 is 3590110002211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 979680284944 + 142319826009 = 989788^2 + 377253^2 .
It is a cyclic number.
It is not a de Polignac number, because 1122000110953 - 213 = 1122000102761 is a prime.
It is not a weakly prime, because it can be changed into another prime (1122000114953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561000055476 + 561000055477.
It is an arithmetic number, because the mean of its divisors is an integer number (561000055477).
Almost surely, 21122000110953 is an apocalyptic number.
It is an amenable number.
1122000110953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122000110953 is an equidigital number, since it uses as much as digits as its factorization.
1122000110953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
The spelling of 1122000110953 in words is "one trillion, one hundred twenty-two billion, one hundred ten thousand, nine hundred fifty-three".
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