Base | Representation |
---|---|
bin | 10000010100111100011… |
… | …101111010101111001001 |
3 | 10222021002011201022121112 |
4 | 100110330131322233021 |
5 | 121340324220034402 |
6 | 2215235022020105 |
7 | 144030141426461 |
oct | 20247435725711 |
9 | 3867064638545 |
10 | 1122000939977 |
11 | 3a2924309915 |
12 | 16154ba17635 |
13 | 81a5bb99058 |
14 | 3c43b410ba1 |
15 | 1e2bc217e52 |
hex | 1053c77abc9 |
1122000939977 has 2 divisors, whose sum is σ = 1122000939978. Its totient is φ = 1122000939976.
The previous prime is 1122000939967. The next prime is 1122000940063. The reversal of 1122000939977 is 7799390002211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1060685770816 + 61315169161 = 1029896^2 + 247619^2 .
It is a cyclic number.
It is not a de Polignac number, because 1122000939977 - 216 = 1122000874441 is a prime.
It is a super-2 number, since 2×11220009399772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1122000939967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561000469988 + 561000469989.
It is an arithmetic number, because the mean of its divisors is an integer number (561000469989).
Almost surely, 21122000939977 is an apocalyptic number.
It is an amenable number.
1122000939977 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122000939977 is an equidigital number, since it uses as much as digits as its factorization.
1122000939977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 428652, while the sum is 50.
The spelling of 1122000939977 in words is "one trillion, one hundred twenty-two billion, nine hundred thirty-nine thousand, nine hundred seventy-seven".
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