Base | Representation |
---|---|
bin | 110100001111110100… |
… | …1011111011100110001 |
3 | 101201121102022122210012 |
4 | 1220133221133130301 |
5 | 3314241212320423 |
6 | 123313301544305 |
7 | 11051265166544 |
oct | 1503751373461 |
9 | 351542278705 |
10 | 112200120113 |
11 | 436470519a4 |
12 | 198b3715095 |
13 | a771271123 |
14 | 560549285b |
15 | 2dba33a078 |
hex | 1a1fa5f731 |
112200120113 has 4 divisors (see below), whose sum is σ = 112200924528. Its totient is φ = 112199315700.
The previous prime is 112200120089. The next prime is 112200120127. The reversal of 112200120113 is 311021002211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 112200120113 - 210 = 112200119089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112200120133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132863 + ... + 491988.
It is an arithmetic number, because the mean of its divisors is an integer number (28050231132).
Almost surely, 2112200120113 is an apocalyptic number.
It is an amenable number.
112200120113 is a deficient number, since it is larger than the sum of its proper divisors (804415).
112200120113 is an equidigital number, since it uses as much as digits as its factorization.
112200120113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 804414.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 112200120113 its reverse (311021002211), we get a palindrome (423221122324).
The spelling of 112200120113 in words is "one hundred twelve billion, two hundred million, one hundred twenty thousand, one hundred thirteen".
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