Base | Representation |
---|---|
bin | 11001100000101110100101… |
… | …001100100100111100101001 |
3 | 112201021020100000011201002001 |
4 | 121200232211030210330221 |
5 | 104201242003231223423 |
6 | 1034344021125011001 |
7 | 32430124414655452 |
oct | 3140564514447451 |
9 | 481236300151061 |
10 | 112200202211113 |
11 | 328289251053a5 |
12 | 10701198853a61 |
13 | 4a7b583a04533 |
14 | 1d9c7396ac129 |
15 | ce88b87a8cad |
hex | 660ba5324f29 |
112200202211113 has 2 divisors, whose sum is σ = 112200202211114. Its totient is φ = 112200202211112.
The previous prime is 112200202211081. The next prime is 112200202211159. The reversal of 112200202211113 is 311112202002211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74518381554409 + 37681820656704 = 8632403^2 + 6138552^2 .
It is a cyclic number.
It is not a de Polignac number, because 112200202211113 - 25 = 112200202211081 is a prime.
It is not a weakly prime, because it can be changed into another prime (112200202011113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56100101105556 + 56100101105557.
It is an arithmetic number, because the mean of its divisors is an integer number (56100101105557).
Almost surely, 2112200202211113 is an apocalyptic number.
It is an amenable number.
112200202211113 is a deficient number, since it is larger than the sum of its proper divisors (1).
112200202211113 is an equidigital number, since it uses as much as digits as its factorization.
112200202211113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 112200202211113 its reverse (311112202002211), we get a palindrome (423312404213324).
The spelling of 112200202211113 in words is "one hundred twelve trillion, two hundred billion, two hundred two million, two hundred eleven thousand, one hundred thirteen".
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