Base | Representation |
---|---|
bin | 10000010100111100100… |
… | …010010110011101110011 |
3 | 10222021002020220100210021 |
4 | 100110330202112131303 |
5 | 121340330014232011 |
6 | 2215235102544311 |
7 | 144030154336621 |
oct | 20247442263563 |
9 | 3867066810707 |
10 | 1122002102131 |
11 | 3a2924a32a79 |
12 | 161550298097 |
13 | 81a5c1b5011 |
14 | 3c43b634511 |
15 | 1e2bc397471 |
hex | 1053c896773 |
1122002102131 has 2 divisors, whose sum is σ = 1122002102132. Its totient is φ = 1122002102130.
The previous prime is 1122002102119. The next prime is 1122002102153. The reversal of 1122002102131 is 1312012002211.
It is a weak prime.
It is an emirp because it is prime and its reverse (1312012002211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1122002102131 - 231 = 1119854618483 is a prime.
It is a super-2 number, since 2×11220021021312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1122002102831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561001051065 + 561001051066.
It is an arithmetic number, because the mean of its divisors is an integer number (561001051066).
Almost surely, 21122002102131 is an apocalyptic number.
1122002102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122002102131 is an equidigital number, since it uses as much as digits as its factorization.
1122002102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1122002102131 its reverse (1312012002211), we get a palindrome (2434014104342).
The spelling of 1122002102131 in words is "one trillion, one hundred twenty-two billion, two million, one hundred two thousand, one hundred thirty-one".
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