Base | Representation |
---|---|
bin | 11001100000101111011100… |
… | …100111011111010111000001 |
3 | 112201021022201210202112110201 |
4 | 121200233130213133113001 |
5 | 104201300404243403433 |
6 | 1034344253301525201 |
7 | 32430156435106222 |
oct | 3140573447372701 |
9 | 481238653675421 |
10 | 112201132012993 |
11 | 32829261a42301 |
12 | 107013b8113801 |
13 | 4a7b6a153396a |
14 | 1d9c7c6d85249 |
15 | ce8920220a7d |
hex | 660bdc9df5c1 |
112201132012993 has 2 divisors, whose sum is σ = 112201132012994. Its totient is φ = 112201132012992.
The previous prime is 112201132012973. The next prime is 112201132012997. The reversal of 112201132012993 is 399210231102211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112144541788224 + 56590224769 = 10589832^2 + 237887^2 .
It is a cyclic number.
It is not a de Polignac number, because 112201132012993 - 217 = 112201131881921 is a prime.
It is not a weakly prime, because it can be changed into another prime (112201132012997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56100566006496 + 56100566006497.
It is an arithmetic number, because the mean of its divisors is an integer number (56100566006497).
Almost surely, 2112201132012993 is an apocalyptic number.
It is an amenable number.
112201132012993 is a deficient number, since it is larger than the sum of its proper divisors (1).
112201132012993 is an equidigital number, since it uses as much as digits as its factorization.
112201132012993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 37.
The spelling of 112201132012993 in words is "one hundred twelve trillion, two hundred one billion, one hundred thirty-two million, twelve thousand, nine hundred ninety-three".
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