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11220131423129 is a prime number
BaseRepresentation
bin1010001101000110001111…
…1100101010001110011001
31110201122010020202121200212
42203101203330222032121
52432312312121020004
635510242431540505
72235425213333126
oct243214374521631
943648106677625
1011220131423129
113636481753292
12131265338a735
13635091414305
142ab0b318d74d
15146cdc1a996e
hexa3463f2a399

11220131423129 has 2 divisors, whose sum is σ = 11220131423130. Its totient is φ = 11220131423128.

The previous prime is 11220131423099. The next prime is 11220131423227. The reversal of 11220131423129 is 92132413102211.

11220131423129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9401288087104 + 1818843336025 = 3066152^2 + 1348645^2 .

It is a cyclic number.

It is not a de Polignac number, because 11220131423129 - 28 = 11220131422873 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11220131423095 and 11220131423104.

It is not a weakly prime, because it can be changed into another prime (11220131423429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610065711564 + 5610065711565.

It is an arithmetic number, because the mean of its divisors is an integer number (5610065711565).

Almost surely, 211220131423129 is an apocalyptic number.

It is an amenable number.

11220131423129 is a deficient number, since it is larger than the sum of its proper divisors (1).

11220131423129 is an equidigital number, since it uses as much as digits as its factorization.

11220131423129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 11220131423129 in words is "eleven trillion, two hundred twenty billion, one hundred thirty-one million, four hundred twenty-three thousand, one hundred twenty-nine".