Base | Representation |
---|---|
bin | 10000010100111101110… |
… | …010100101000010010011 |
3 | 10222021010201110212011121 |
4 | 100110331302211002103 |
5 | 121340400410231311 |
6 | 2215241133423111 |
7 | 144030531162232 |
oct | 20247562450223 |
9 | 3867121425147 |
10 | 1122023133331 |
11 | 3a2935898031 |
12 | 16155733aa97 |
13 | 81a63669909 |
14 | 3c44034ab19 |
15 | 1e2be14db71 |
hex | 1053dca5093 |
1122023133331 has 2 divisors, whose sum is σ = 1122023133332. Its totient is φ = 1122023133330.
The previous prime is 1122023133271. The next prime is 1122023133353. The reversal of 1122023133331 is 1333313202211.
It is a strong prime.
It is an emirp because it is prime and its reverse (1333313202211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1122023133331 is a prime.
It is a super-2 number, since 2×11220231333312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1122023133296 and 1122023133305.
It is not a weakly prime, because it can be changed into another prime (1122023136331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561011566665 + 561011566666.
It is an arithmetic number, because the mean of its divisors is an integer number (561011566666).
Almost surely, 21122023133331 is an apocalyptic number.
1122023133331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122023133331 is an equidigital number, since it uses as much as digits as its factorization.
1122023133331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1122023133331 its reverse (1333313202211), we get a palindrome (2455336335542).
The spelling of 1122023133331 in words is "one trillion, one hundred twenty-two billion, twenty-three million, one hundred thirty-three thousand, three hundred thirty-one".
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