Base | Representation |
---|---|
bin | 11001100000110010100001… |
… | …111010100011110011011011 |
3 | 112201021122021111022120102112 |
4 | 121200302201322203303123 |
5 | 104201324144140422413 |
6 | 1034350001545022535 |
7 | 32430334450431143 |
oct | 3140624172436333 |
9 | 481248244276375 |
10 | 112204442123483 |
11 | 3282a700462306 |
12 | 10701b80784a4b |
13 | 4a7baab245c18 |
14 | 1d9ca1c833923 |
15 | ce8a65b1e2a8 |
hex | 660ca1ea3cdb |
112204442123483 has 2 divisors, whose sum is σ = 112204442123484. Its totient is φ = 112204442123482.
The previous prime is 112204442123387. The next prime is 112204442123509. The reversal of 112204442123483 is 384321244402211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112204442123483 - 218 = 112204441861339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112204442123483.
It is not a weakly prime, because it can be changed into another prime (112204442143483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56102221061741 + 56102221061742.
It is an arithmetic number, because the mean of its divisors is an integer number (56102221061742).
Almost surely, 2112204442123483 is an apocalyptic number.
112204442123483 is a deficient number, since it is larger than the sum of its proper divisors (1).
112204442123483 is an equidigital number, since it uses as much as digits as its factorization.
112204442123483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 294912, while the sum is 41.
Adding to 112204442123483 its reverse (384321244402211), we get a palindrome (496525686525694).
The spelling of 112204442123483 in words is "one hundred twelve trillion, two hundred four billion, four hundred forty-two million, one hundred twenty-three thousand, four hundred eighty-three".
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